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More services...AC/DC module - joule heating - contact resistance
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3 Replies
Last post: August 25, 2010 9:36am UTC
August 24, 2010 1:02pm UTC
AC/DC module - joule heating - contact resistance
Hi there COMSOL users
My issue is straightforward:
I describe in my model a typical resistive heating by current passage at the contact of two surfaces (axial symmetry 2D).
In the boundary conditions, I've associated a contact resistance to my contact pair (the interface between my subdomains).
QUESTION: I would like to know the physical meaning of the so called thickness 'd' , which in other tutorials is left equal to 1m without, apparently, any relation to the geometry.
Thank you very much
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August 24, 2010 6:41pm UTC in response to Paolo Di Napoli
Re: AC/DC module - joule heating - contact resistance
Hi
probably its straightforward, but to allow us other to better understand you could you pls define COMSOL version and which of the seveal "thickness" you are referring to, in which window, defining whixh physics/application mode and/or boundary condition
it would help to give you a reasonnable answer ;)
--
Good luck
Ivar
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August 25, 2010 7:59am UTC in response to Ivar Kjelberg
Re: AC/DC module - joule heating - contact resistance
Of course
Version 3.5.
In module: Conductive Media DC:
Menu Physics -> Boundary settings: I select the contact pair and I assign Contact Resistance as boundary condition;
two values are now to be inputed: the electric conductivity sigma and the thickness d.
I am referring to this thickness value.
Thank you very much
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August 25, 2010 9:36am UTC in response to Paolo Di Napoli
Re: AC/DC module - joule heating - contact resistance
Hi
well the term thickness is used in different modules having slightly different meanings. In 2D (which is in fact a 3D but with the depth "z" or "thickness" set to defautl 1[m] (dependson application mode and physics though)
But for you I understand the "thickness" of being the true (but non-apparent) film thickness for you thin fim contact resistance. It's required to calculate correctly the resistivity from the bulk volumic resisitivity. So check carefully your units for all value you set in for coherent units all over
--
Good luck
Ivar
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